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Find the minimum value of f(x) = 4x^2 - 16x + 15. (2023)

Practice Questions

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Find the minimum value of f(x) = 4x^2 - 16x + 15. (2023)
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Questions & Step-by-step Solutions

1 item
Q
Q: Find the minimum value of f(x) = 4x^2 - 16x + 15. (2023)
Solution: The minimum occurs at x = -b/(2a) = 16/(2*4) = 2. f(2) = 4(2^2) - 16(2) + 15 = 1.
Steps: 0

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