Find the maximum value of f(x) = -3x^2 + 12x - 5. (2020)

Practice Questions

1 question
Q1
Find the maximum value of f(x) = -3x^2 + 12x - 5. (2020)
  1. 1
  2. 4
  3. 7
  4. 9

Questions & Step-by-step Solutions

1 item
Q
Q: Find the maximum value of f(x) = -3x^2 + 12x - 5. (2020)
Solution: The maximum occurs at x = -b/(2a) = -12/(-6) = 2. f(2) = -3(2^2) + 12(2) - 5 = 7.
Steps: 0

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