Find the critical points of the function f(x) = x^3 - 3x^2 + 4.

Practice Questions

1 question
Q1
Find the critical points of the function f(x) = x^3 - 3x^2 + 4.
  1. x = 0, 2
  2. x = 1, 2
  3. x = 1, 3
  4. x = 0, 1

Questions & Step-by-step Solutions

1 item
Q
Q: Find the critical points of the function f(x) = x^3 - 3x^2 + 4.
Solution: To find critical points, set f'(x) = 0. f'(x) = 3x^2 - 6x = 3x(x - 2). Critical points are x = 0 and x = 2.
Steps: 8

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