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Determine the minimum value of the function f(x) = x^2 - 4x + 6. (2020)

Practice Questions

1 question
Q1
Determine the minimum value of the function f(x) = x^2 - 4x + 6. (2020)
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Questions & Step-by-step Solutions

1 item
Q
Q: Determine the minimum value of the function f(x) = x^2 - 4x + 6. (2020)
Solution: The function is a upward-opening parabola. The minimum occurs at x = -b/(2a) = 4/(2*1) = 2. f(2) = 2^2 - 4(2) + 6 = 2.
Steps: 0

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