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An object is dropped from a height of 20 m. What is its potential energy at the
An object is dropped from a height of 20 m. What is its potential energy at the top? (2021)
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An object is dropped from a height of 20 m. What is its potential energy at the top? (2021)
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Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 20 m = 980 J (approximately 400 J for 1 kg)
Questions & Step-by-step Solutions
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Q: An object is dropped from a height of 20 m. What is its potential energy at the top? (2021)
Solution:
Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 20 m = 980 J (approximately 400 J for 1 kg)
Steps: 6
Show Steps
Step 1: Identify the formula for potential energy (PE). The formula is PE = m * g * h.
Step 2: Determine the values needed for the formula: mass (m), gravitational acceleration (g), and height (h).
Step 3: Use the given values: mass (m) = 5 kg, gravitational acceleration (g) = 9.8 m/s^2, height (h) = 20 m.
Step 4: Plug the values into the formula: PE = 5 kg * 9.8 m/s^2 * 20 m.
Step 5: Calculate the potential energy: 5 * 9.8 * 20 = 980 J.
Step 6: Note that for 1 kg, the potential energy would be approximately 400 J.
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