A solenoid has a length of 1 m and a cross-sectional area of 0.01 m². If the magnetic field inside the solenoid is 0.2 T, what is the magnetic flux through one turn of the solenoid?
Practice Questions
1 question
Q1
A solenoid has a length of 1 m and a cross-sectional area of 0.01 m². If the magnetic field inside the solenoid is 0.2 T, what is the magnetic flux through one turn of the solenoid?
0.002 Wb
0.01 Wb
0.02 Wb
0.1 Wb
Magnetic flux (Φ) = B * A = 0.2 T * 0.01 m² = 0.002 Wb. For one turn, the flux is 0.002 Wb.
Questions & Step-by-step Solutions
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Q
Q: A solenoid has a length of 1 m and a cross-sectional area of 0.01 m². If the magnetic field inside the solenoid is 0.2 T, what is the magnetic flux through one turn of the solenoid?
Solution: Magnetic flux (Φ) = B * A = 0.2 T * 0.01 m² = 0.002 Wb. For one turn, the flux is 0.002 Wb.
Steps: 6
Step 1: Identify the formula for magnetic flux, which is Φ = B * A.
Step 2: Determine the values needed for the formula. Here, B (magnetic field) is 0.2 T and A (cross-sectional area) is 0.01 m².
Step 3: Substitute the values into the formula: Φ = 0.2 T * 0.01 m².
Step 4: Calculate the result: 0.2 * 0.01 = 0.002.
Step 5: State the unit of magnetic flux, which is Weber (Wb).
Step 6: Conclude that the magnetic flux through one turn of the solenoid is 0.002 Wb.
