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A refrigerator operates between 250 K and 300 K. What is its coefficient of perf
A refrigerator operates between 250 K and 300 K. What is its coefficient of performance (COP)? (2022)
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A refrigerator operates between 250 K and 300 K. What is its coefficient of performance (COP)? (2022)
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COP = T_cold / (T_hot - T_cold) = 250 K / (300 K - 250 K) = 250 / 50 = 5.0.
Questions & Step-by-step Solutions
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Q: A refrigerator operates between 250 K and 300 K. What is its coefficient of performance (COP)? (2022)
Solution:
COP = T_cold / (T_hot - T_cold) = 250 K / (300 K - 250 K) = 250 / 50 = 5.0.
Steps: 7
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Step 1: Identify the temperatures involved. The cold temperature (T_cold) is 250 K and the hot temperature (T_hot) is 300 K.
Step 2: Calculate the difference between the hot and cold temperatures. This is done by subtracting T_cold from T_hot: 300 K - 250 K = 50 K.
Step 3: Use the formula for the coefficient of performance (COP) of a refrigerator: COP = T_cold / (T_hot - T_cold).
Step 4: Substitute the values into the formula: COP = 250 K / (300 K - 250 K).
Step 5: Simplify the equation: COP = 250 K / 50 K.
Step 6: Perform the division: 250 / 50 = 5.0.
Step 7: Conclude that the coefficient of performance (COP) of the refrigerator is 5.0.
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