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A pendulum of length 1 m swings with a small amplitude. What is its approximate
A pendulum of length 1 m swings with a small amplitude. What is its approximate time period? (2023)
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Q1
A pendulum of length 1 m swings with a small amplitude. What is its approximate time period? (2023)
1 s
2 s
0.5 s
0.25 s
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Time period (T) = 2π√(L/g) ≈ 2π√(1/9.8) ≈ 2 s.
Questions & Step-by-step Solutions
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Q
Q: A pendulum of length 1 m swings with a small amplitude. What is its approximate time period? (2023)
Solution:
Time period (T) = 2π√(L/g) ≈ 2π√(1/9.8) ≈ 2 s.
Steps: 7
Show Steps
Step 1: Identify the formula for the time period (T) of a pendulum, which is T = 2π√(L/g).
Step 2: Determine the length (L) of the pendulum, which is given as 1 meter.
Step 3: Identify the acceleration due to gravity (g), which is approximately 9.8 m/s².
Step 4: Substitute the values into the formula: T = 2π√(1/9.8).
Step 5: Calculate the value inside the square root: 1/9.8 ≈ 0.10204.
Step 6: Find the square root of 0.10204, which is approximately 0.319.
Step 7: Multiply by 2π: T ≈ 2 * 3.14 * 0.319 ≈ 2.0 seconds.
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