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A number leaves a remainder of 4 when divided by 9 and a remainder of 2 when divided by 5. What is the smallest such number? (2023)

Practice Questions

1 question
Q1
A number leaves a remainder of 4 when divided by 9 and a remainder of 2 when divided by 5. What is the smallest such number? (2023)
  1. 14
  2. 23
  3. 32
  4. 41

Questions & Step-by-step Solutions

1 item
Q
Q: A number leaves a remainder of 4 when divided by 9 and a remainder of 2 when divided by 5. What is the smallest such number? (2023)
Solution: The smallest number that satisfies both conditions is 23 (23 % 9 = 5 and 23 % 5 = 3).
Steps: 0

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