A mixture contains 60% of liquid X and 40% of liquid Y. If 5 liters of liquid Y is added, what will be the new percentage of liquid X in the mixture if the total volume becomes 25 liters?
Practice Questions
1 question
Q1
A mixture contains 60% of liquid X and 40% of liquid Y. If 5 liters of liquid Y is added, what will be the new percentage of liquid X in the mixture if the total volume becomes 25 liters?
60%
50%
40%
70%
Initial volume of X = 60% of 20 liters = 12 liters. New total = 25 liters. New percentage of X = (12/25) * 100 = 48%.
Questions & Step-by-step Solutions
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Q
Q: A mixture contains 60% of liquid X and 40% of liquid Y. If 5 liters of liquid Y is added, what will be the new percentage of liquid X in the mixture if the total volume becomes 25 liters?
Solution: Initial volume of X = 60% of 20 liters = 12 liters. New total = 25 liters. New percentage of X = (12/25) * 100 = 48%.
Steps: 8
Step 1: Understand that the mixture initially has 60% liquid X and 40% liquid Y.
Step 2: Calculate the initial total volume of the mixture before adding liquid Y. Since we know the percentages, we can assume the initial total volume is 20 liters (because 60% + 40% = 100%).
Step 3: Calculate the initial volume of liquid X. This is 60% of 20 liters, which is 12 liters.
Step 4: Add 5 liters of liquid Y to the mixture. The new total volume of the mixture is 20 liters + 5 liters = 25 liters.
Step 5: The volume of liquid X remains the same at 12 liters since we only added liquid Y.
Step 6: Calculate the new percentage of liquid X in the mixture. This is done by dividing the volume of liquid X (12 liters) by the new total volume (25 liters) and then multiplying by 100.
