A jar contains 5 green, 7 yellow, and 8 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
Practice Questions
1 question
Q1
A jar contains 5 green, 7 yellow, and 8 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
1/3
5/20
12/20
1/2
Total marbles = 5 + 7 + 8 = 20. Green or yellow = 5 + 7 = 12. Probability = 12/20 = 3/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A jar contains 5 green, 7 yellow, and 8 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
Solution: Total marbles = 5 + 7 + 8 = 20. Green or yellow = 5 + 7 = 12. Probability = 12/20 = 3/5.
Steps: 7
Step 1: Count the number of green marbles in the jar. There are 5 green marbles.
Step 2: Count the number of yellow marbles in the jar. There are 7 yellow marbles.
Step 3: Count the number of blue marbles in the jar. There are 8 blue marbles.
Step 4: Add the total number of marbles together: 5 (green) + 7 (yellow) + 8 (blue) = 20 total marbles.
Step 5: Add the number of green and yellow marbles together: 5 (green) + 7 (yellow) = 12 marbles that are either green or yellow.
Step 6: To find the probability of drawing a green or yellow marble, divide the number of green or yellow marbles (12) by the total number of marbles (20): 12/20.
Step 7: Simplify the fraction 12/20 to its lowest terms: 12/20 = 3/5.
