A gas expands from a volume of 2 m³ to 5 m³ at a constant pressure of 100 kPa. What is the work done by the gas? (2022)

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Q: A gas expands from a volume of 2 m³ to 5 m³ at a constant pressure of 100 kPa. What is the work done by the gas? (2022)

Solution: Work done (W) = P * ΔV = 100 kPa * (5 m³ - 2 m³) = 100 kPa * 3 m³ = 300 kJ.

Steps: 9

Step 1: Identify the initial volume of the gas, which is 2 m³.
Step 2: Identify the final volume of the gas, which is 5 m³.
Step 3: Calculate the change in volume (ΔV) by subtracting the initial volume from the final volume: ΔV = 5 m³ - 2 m³.
Step 4: Calculate ΔV, which equals 3 m³.
Step 5: Identify the constant pressure (P) at which the gas expands, which is 100 kPa.
Step 6: Use the formula for work done (W) by the gas: W = P * ΔV.
Step 7: Substitute the values into the formula: W = 100 kPa * 3 m³.
Step 8: Calculate the work done: W = 300 kPa·m³.
Step 9: Convert kPa·m³ to kJ (1 kPa·m³ = 1 kJ), so W = 300 kJ.