A container has 30 liters of a mixture of water and alcohol in the ratio 2:1. How much alcohol is in the container?
Practice Questions
1 question
Q1
A container has 30 liters of a mixture of water and alcohol in the ratio 2:1. How much alcohol is in the container?
5 liters
10 liters
15 liters
20 liters
Total parts = 2 + 1 = 3. Volume of alcohol = (1/3) * 30 = 10 liters.
Questions & Step-by-step Solutions
1 item
Q
Q: A container has 30 liters of a mixture of water and alcohol in the ratio 2:1. How much alcohol is in the container?
Solution: Total parts = 2 + 1 = 3. Volume of alcohol = (1/3) * 30 = 10 liters.
Steps: 6
Step 1: Understand the total volume of the mixture, which is 30 liters.
Step 2: Identify the ratio of water to alcohol, which is 2:1.
Step 3: Calculate the total number of parts in the ratio by adding the parts together: 2 (for water) + 1 (for alcohol) = 3 parts.
Step 4: Determine the volume of alcohol by finding the fraction of the total volume that corresponds to alcohol. Since alcohol is 1 part out of 3, the fraction is 1/3.
Step 5: Multiply the total volume (30 liters) by the fraction for alcohol (1/3): (1/3) * 30 = 10 liters.
Step 6: Conclude that there are 10 liters of alcohol in the container.
