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A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is
A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is the force acting on the charge? (2023)
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Practice Questions
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Q1
A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is the force acting on the charge? (2023)
20 N
200 N
2 N
0.2 N
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Force F = qE = (10 × 10^-6 C) * (2000 N/C) = 0.02 N = 20 N.
Questions & Step-by-step Solutions
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Q
Q: A charge of +10 µC is placed in an electric field of strength 2000 N/C. What is the force acting on the charge? (2023)
Solution:
Force F = qE = (10 × 10^-6 C) * (2000 N/C) = 0.02 N = 20 N.
Steps: 6
Show Steps
Step 1: Identify the charge value. The charge is +10 µC (microcoulombs). Convert this to coulombs: 10 µC = 10 × 10^-6 C.
Step 2: Identify the electric field strength. The electric field strength is given as 2000 N/C.
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (10 × 10^-6 C) * (2000 N/C).
Step 5: Calculate the force: F = 10 × 2000 × 10^-6 N = 20000 × 10^-6 N = 0.02 N.
Step 6: Convert the force to a more understandable unit if needed: 0.02 N is the same as 20 mN (millinewtons).
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