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A 2 kg object is lifted to a height of 3 m. What is the work done against gravit
A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)
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Practice Questions
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Q1
A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)
58.8 J
19.6 J
29.4 J
39.2 J
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Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J
Questions & Step-by-step Solutions
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Q
Q: A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)
Solution:
Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 3 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work Done = m * g * h.
Step 5: Substitute the values into the formula: Work Done = 2 kg * 9.8 m/s² * 3 m.
Step 6: Calculate the result: 2 * 9.8 * 3 = 58.8 J.
Step 7: Conclude that the work done against gravity is 58.8 Joules.
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