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A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done
A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?
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Q1
A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?
468,750 J
375,000 J
250,000 J
187,500 J
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Work done = Change in Kinetic Energy = 0.5 * m * v² = 0.5 * 1500 kg * (25 m/s)² = 468,750 J.
Questions & Step-by-step Solutions
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Q
Q: A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?
Solution:
Work done = Change in Kinetic Energy = 0.5 * m * v² = 0.5 * 1500 kg * (25 m/s)² = 468,750 J.
Steps: 9
Show Steps
Step 1: Identify the mass of the car, which is 1500 kg.
Step 2: Identify the final speed of the car, which is 25 m/s.
Step 3: Understand that the car starts from rest, so the initial speed is 0 m/s.
Step 4: Recall the formula for kinetic energy: KE = 0.5 * m * v².
Step 5: Substitute the mass (1500 kg) and the final speed (25 m/s) into the formula.
Step 6: Calculate the square of the speed: (25 m/s)² = 625 m²/s².
Step 7: Multiply the mass by the square of the speed: 1500 kg * 625 m²/s² = 937500 kg*m²/s².
Step 8: Multiply by 0.5: 0.5 * 937500 = 468750 J.
Step 9: Conclude that the work done on the car is 468750 Joules.
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