A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)

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Q: A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)

Solution: Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Steps: 9

Step 1: Identify the mass of the object, which is 12 kg.
Step 2: Identify the force applied to the object, which is 36 N.
Step 3: Use the formula for acceleration, which is Acceleration = Force / Mass.
Step 4: Plug in the values: Acceleration = 36 N / 12 kg.
Step 5: Calculate the acceleration: 36 N / 12 kg = 3 m/s².
Step 6: Identify the initial velocity of the object, which is 0 m/s (since it is at rest).
Step 7: Use the formula for velocity after a certain time, which is Velocity = Initial velocity + (Acceleration × Time).
Step 8: Plug in the values: Velocity = 0 m/s + (3 m/s² × 3 s).
Step 9: Calculate the velocity: 0 m/s + 9 m/s = 9 m/s.