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A 10 kg object is lifted to a height of 5 m. What is the potential energy gained
A 10 kg object is lifted to a height of 5 m. What is the potential energy gained? (Take g = 9.8 m/s²) (2021)
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Practice Questions
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Q1
A 10 kg object is lifted to a height of 5 m. What is the potential energy gained? (Take g = 9.8 m/s²) (2021)
490 J
980 J
390 J
590 J
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Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 5 m = 490 J.
Questions & Step-by-step Solutions
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Q
Q: A 10 kg object is lifted to a height of 5 m. What is the potential energy gained? (Take g = 9.8 m/s²) (2021)
Solution:
Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 5 m = 490 J.
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 10 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. We are given that g = 9.8 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = mgh.
Step 5: Substitute the values into the formula: PE = 10 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 10 × 9.8 × 5 = 490 J.
Step 7: Conclude that the potential energy gained is 490 Joules.
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