What is the vapor pressure of a solution containing 1 mole of non-volatile solute in 3 moles of solvent if the vapor pressure of the pure solvent is 100 mmHg?

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75 mmHg
100 mmHg
25 mmHg
50 mmHg

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Q: What is the vapor pressure of a solution containing 1 mole of non-volatile solute in 3 moles of solvent if the vapor pressure of the pure solvent is 100 mmHg?

Solution: Using Raoult's law, P_solution = X_solvent * P°_solvent. X_solvent = 3/(1+3) = 0.75, so P_solution = 0.75 * 100 mmHg = 75 mmHg.

Steps: 6

Step 1: Identify the number of moles of solute and solvent. We have 1 mole of non-volatile solute and 3 moles of solvent.
Step 2: Calculate the total number of moles in the solution. Total moles = moles of solute + moles of solvent = 1 + 3 = 4 moles.
Step 3: Calculate the mole fraction of the solvent (X_solvent). X_solvent = moles of solvent / total moles = 3 / 4 = 0.75.
Step 4: Use Raoult's law to find the vapor pressure of the solution. Raoult's law states that P_solution = X_solvent * P°_solvent.
Step 5: Substitute the values into the equation. P_solution = 0.75 * 100 mmHg.
Step 6: Calculate P_solution. P_solution = 75 mmHg.

What is the vapor pressure of a solution containing 1 mole of non-volatile solute in 3 moles of solvent if the vapor pressure of the pure solvent is 100 mmHg?

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