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What is the vapor pressure of a solution containing 1 mole of a non-volatile sol
What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 3 moles of solvent, assuming ideal behavior?
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Practice Questions
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Q1
What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 3 moles of solvent, assuming ideal behavior?
0.25 P0
0.75 P0
1.0 P0
0.5 P0
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Vapor pressure lowering = (moles of solute / total moles) * P0 = (1 / (1 + 3)) * P0 = 0.25 P0, so vapor pressure = P0 - 0.25 P0 = 0.75 P0.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 3 moles of solvent, assuming ideal behavior?
Solution:
Vapor pressure lowering = (moles of solute / total moles) * P0 = (1 / (1 + 3)) * P0 = 0.25 P0, so vapor pressure = P0 - 0.25 P0 = 0.75 P0.
Steps: 5
Show Steps
Step 1: Identify the number of moles of solute and solvent. Here, we have 1 mole of solute and 3 moles of solvent.
Step 2: Calculate the total number of moles in the solution. Total moles = moles of solute + moles of solvent = 1 + 3 = 4 moles.
Step 3: Calculate the mole fraction of the solute. Mole fraction of solute = moles of solute / total moles = 1 / 4 = 0.25.
Step 4: Use the mole fraction to find the vapor pressure lowering. Vapor pressure lowering = mole fraction of solute * P0 = 0.25 * P0.
Step 5: Calculate the new vapor pressure of the solution. New vapor pressure = P0 - vapor pressure lowering = P0 - 0.25 P0 = 0.75 P0.
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