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What is the van 't Hoff factor (i) for a strong electrolyte like NaCl in solutio
What is the van 't Hoff factor (i) for a strong electrolyte like NaCl in solution?
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Q1
What is the van 't Hoff factor (i) for a strong electrolyte like NaCl in solution?
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NaCl dissociates into two ions (Na+ and Cl-), so the van 't Hoff factor (i) is 2.
Questions & Step-by-step Solutions
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Q: What is the van 't Hoff factor (i) for a strong electrolyte like NaCl in solution?
Solution:
NaCl dissociates into two ions (Na+ and Cl-), so the van 't Hoff factor (i) is 2.
Steps: 5
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Step 1: Understand that a strong electrolyte is a substance that completely dissociates into ions in solution.
Step 2: Identify the strong electrolyte in question, which is NaCl (sodium chloride).
Step 3: Recognize that when NaCl dissolves in water, it breaks apart into two separate ions: Na+ (sodium ion) and Cl- (chloride ion).
Step 4: Count the total number of ions produced from one formula unit of NaCl. In this case, there are 2 ions (Na+ and Cl-).
Step 5: Conclude that the van 't Hoff factor (i) is equal to the number of particles (ions) produced, which is 2.
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