What is the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g) from C(s) and O2(g) given the following reactions: C(s) + O2(g) → CO2(g) ΔH° = -393.5 kJ?
Practice Questions
1 question
Q1
What is the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g) from C(s) and O2(g) given the following reactions: C(s) + O2(g) → CO2(g) ΔH° = -393.5 kJ?
-393.5 kJ
393.5 kJ
0 kJ
-273.15 kJ
The standard enthalpy change for the formation of CO2(g) is directly given as ΔH° = -393.5 kJ.
Questions & Step-by-step Solutions
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Q
Q: What is the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g) from C(s) and O2(g) given the following reactions: C(s) + O2(g) → CO2(g) ΔH° = -393.5 kJ?
Solution: The standard enthalpy change for the formation of CO2(g) is directly given as ΔH° = -393.5 kJ.
