What is the integrated rate law for a second-order reaction?
Practice Questions
1 question
Q1
What is the integrated rate law for a second-order reaction?
[A] = [A]0 - kt
1/[A] = 1/[A]0 + kt
[A] = [A]0e^(-kt)
ln[A] = ln[A]0 - kt
The integrated rate law for a second-order reaction is given by 1/[A] = 1/[A]0 + kt, where [A]0 is the initial concentration.
Questions & Step-by-step Solutions
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Q
Q: What is the integrated rate law for a second-order reaction?
Solution: The integrated rate law for a second-order reaction is given by 1/[A] = 1/[A]0 + kt, where [A]0 is the initial concentration.
Steps: 4
Step 1: Understand that a second-order reaction means the rate of the reaction depends on the concentration of one reactant squared or on the concentrations of two reactants.
Step 2: The integrated rate law is a mathematical expression that relates the concentration of the reactant to time.
Step 3: For a second-order reaction, the formula is 1/[A] = 1/[A]0 + kt.
Step 4: In this formula, [A] is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, k is the rate constant, and t is the time elapsed.
