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What is the fundamental frequency of a pipe open at both ends that is 2 meters l
What is the fundamental frequency of a pipe open at both ends that is 2 meters long?
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Practice Questions
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Q1
What is the fundamental frequency of a pipe open at both ends that is 2 meters long?
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The fundamental frequency is given by f = v/λ; for a pipe open at both ends, λ = 2L, so f = v/(2L) = 343/(2*2) = 42.875 Hz.
Questions & Step-by-step Solutions
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Q
Q: What is the fundamental frequency of a pipe open at both ends that is 2 meters long?
Solution:
The fundamental frequency is given by f = v/λ; for a pipe open at both ends, λ = 2L, so f = v/(2L) = 343/(2*2) = 42.875 Hz.
Steps: 7
Show Steps
Step 1: Understand that we need to find the fundamental frequency of a pipe that is open at both ends.
Step 2: Know that the formula for frequency (f) is f = v/λ, where v is the speed of sound and λ is the wavelength.
Step 3: For a pipe open at both ends, the wavelength (λ) is equal to 2 times the length of the pipe (L). So, λ = 2L.
Step 4: Since the length of the pipe (L) is 2 meters, we calculate λ: λ = 2 * 2 = 4 meters.
Step 5: The speed of sound in air (v) is approximately 343 meters per second.
Step 6: Now, substitute the values into the frequency formula: f = v/λ = 343 / 4.
Step 7: Calculate the frequency: f = 343 / 4 = 85.75 Hz.
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