What is the equivalent weight of sulfuric acid (H2SO4) for the purpose of neutralization?
Practice Questions
1 question
Q1
What is the equivalent weight of sulfuric acid (H2SO4) for the purpose of neutralization?
49 g
98 g
24.5 g
196 g
Equivalent weight = molar mass / n, where n = number of H+ ions. Molar mass of H2SO4 = 98 g/mol, n = 2. Therefore, equivalent weight = 98 g / 2 = 49 g.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equivalent weight of sulfuric acid (H2SO4) for the purpose of neutralization?
Solution: Equivalent weight = molar mass / n, where n = number of H+ ions. Molar mass of H2SO4 = 98 g/mol, n = 2. Therefore, equivalent weight = 98 g / 2 = 49 g.
Steps: 6
Step 1: Understand that we need to find the equivalent weight of sulfuric acid (H2SO4) for neutralization.
Step 2: Recall the formula for equivalent weight: Equivalent weight = molar mass / n.
Step 3: Identify the molar mass of sulfuric acid (H2SO4). It is 98 g/mol.
Step 4: Determine the value of n, which is the number of H+ ions that sulfuric acid can donate. For H2SO4, n = 2.
Step 5: Plug the values into the formula: Equivalent weight = 98 g/mol / 2.
Step 6: Calculate the equivalent weight: 98 g / 2 = 49 g.
