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What is the equilibrium constant (K) for a reaction with ΔG° = -40 kJ at 298 K?

Practice Questions

1 question
Q1
What is the equilibrium constant (K) for a reaction with ΔG° = -40 kJ at 298 K?
  1. 10
  2. 100
  3. 1000
  4. 10000

Questions & Step-by-step Solutions

1 item
Q
Q: What is the equilibrium constant (K) for a reaction with ΔG° = -40 kJ at 298 K?
Solution: ΔG° = -RTln(K); K = e^(-ΔG°/RT) = e^(40,000/(8.314*298)) ≈ 1000.
Steps: 0

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