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What is the enthalpy change when 4 moles of a substance release 800 J of heat?
What is the enthalpy change when 4 moles of a substance release 800 J of heat?
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Q1
What is the enthalpy change when 4 moles of a substance release 800 J of heat?
200 J/mol
400 J/mol
100 J/mol
300 J/mol
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ΔH = q/n = -800 J / 4 mol = -200 J/mol.
Questions & Step-by-step Solutions
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Q
Q: What is the enthalpy change when 4 moles of a substance release 800 J of heat?
Solution:
ΔH = q/n = -800 J / 4 mol = -200 J/mol.
Steps: 5
Show Steps
Step 1: Identify the amount of heat released, which is 800 J.
Step 2: Identify the number of moles of the substance, which is 4 moles.
Step 3: Use the formula for enthalpy change (ΔH), which is ΔH = q/n, where q is the heat and n is the number of moles.
Step 4: Substitute the values into the formula: ΔH = -800 J / 4 mol.
Step 5: Calculate the result: ΔH = -200 J/mol.
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