What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the standard enthalpy of formation of NH3(g) is -45.9 kJ/mol?
Practice Questions
1 question
Q1
What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the standard enthalpy of formation of NH3(g) is -45.9 kJ/mol?
-91.8 kJ
45.9 kJ
0 kJ
91.8 kJ
The enthalpy change for the reaction is 2 times the standard enthalpy of formation of NH3(g), which is -45.9 kJ/mol, giving -91.8 kJ.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the standard enthalpy of formation of NH3(g) is -45.9 kJ/mol?
Solution: The enthalpy change for the reaction is 2 times the standard enthalpy of formation of NH3(g), which is -45.9 kJ/mol, giving -91.8 kJ.
Steps: 6
Step 1: Identify the reaction: N2(g) + 3H2(g) → 2NH3(g).
Step 2: Understand that the standard enthalpy of formation of NH3(g) is given as -45.9 kJ/mol.
Step 3: Note that the reaction produces 2 moles of NH3(g).
Step 4: Calculate the total enthalpy change by multiplying the standard enthalpy of formation of NH3(g) by the number of moles produced: 2 moles × -45.9 kJ/mol.
