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What is the energy stored in a capacitor of capacitance 10μF charged to a potent
What is the energy stored in a capacitor of capacitance 10μF charged to a potential difference of 50V?
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Practice Questions
1 question
Q1
What is the energy stored in a capacitor of capacitance 10μF charged to a potential difference of 50V?
0.0125 J
0.025 J
0.05 J
0.1 J
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U = 1/2 * C * V² = 1/2 * (10 × 10^-6 F) * (50 V)² = 0.0125 J.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the energy stored in a capacitor of capacitance 10μF charged to a potential difference of 50V?
Solution:
U = 1/2 * C * V² = 1/2 * (10 × 10^-6 F) * (50 V)² = 0.0125 J.
Steps: 8
Show Steps
Step 1: Identify the formula for energy stored in a capacitor, which is U = 1/2 * C * V².
Step 2: Identify the values given in the problem: capacitance (C) = 10μF and potential difference (V) = 50V.
Step 3: Convert the capacitance from microfarads to farads: 10μF = 10 × 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (10 × 10^-6 F) * (50 V)².
Step 5: Calculate (50 V)², which is 2500 V².
Step 6: Multiply 10 × 10^-6 F by 2500 V² to get 0.025 J.
Step 7: Multiply by 1/2: 0.025 J * 1/2 = 0.0125 J.
Step 8: Conclude that the energy stored in the capacitor is 0.0125 J.
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