What is the energy of a photon emitted during the transition from n=3 to n=2 in a hydrogen atom?
Practice Questions
1 question
Q1
What is the energy of a photon emitted during the transition from n=3 to n=2 in a hydrogen atom?
10.2 eV
1.89 eV
12.1 eV
3.4 eV
The energy of the photon can be calculated using the Rydberg formula. The transition from n=3 to n=2 emits a photon of energy approximately 1.89 eV.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the energy of a photon emitted during the transition from n=3 to n=2 in a hydrogen atom?
Solution: The energy of the photon can be calculated using the Rydberg formula. The transition from n=3 to n=2 emits a photon of energy approximately 1.89 eV.
Steps: 8
Step 1: Understand that in a hydrogen atom, electrons can exist in different energy levels, which are represented by 'n' values (like n=1, n=2, n=3, etc.).
Step 2: Identify the initial and final energy levels for the transition. Here, the electron is moving from n=3 (higher energy level) to n=2 (lower energy level).
Step 3: Use the Rydberg formula to calculate the energy of the photon emitted during this transition. The formula is: E = 13.6 eV * (1/n_final^2 - 1/n_initial^2).
Step 4: Plug in the values into the formula: E = 13.6 eV * (1/2^2 - 1/3^2).
