What is the electric field due to a point charge of +4μC at a distance of 0.1m?
Practice Questions
1 question
Q1
What is the electric field due to a point charge of +4μC at a distance of 0.1m?
36000 N/C
40000 N/C
44000 N/C
48000 N/C
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (0.1 m)² = 36000 N/C.
Questions & Step-by-step Solutions
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Q
Q: What is the electric field due to a point charge of +4μC at a distance of 0.1m?
Solution: Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (0.1 m)² = 36000 N/C.
Steps: 7
Step 1: Identify the formula for the electric field (E) due to a point charge. The formula is E = k * |q| / r².
Step 2: Identify the values needed for the formula. Here, k (Coulomb's constant) is 9 × 10^9 N m²/C², q (the charge) is +4μC (which is 4 × 10^-6 C), and r (the distance) is 0.1m.
Step 3: Substitute the values into the formula. E = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (0.1 m)².
Step 4: Calculate the denominator (0.1 m)², which is 0.01 m².
Step 5: Now calculate the electric field: E = (9 × 10^9) * (4 × 10^-6) / 0.01.
Step 6: Multiply 9 × 10^9 by 4 × 10^-6 to get 36,000.
Step 7: Finally, divide 36,000 by 0.01 to get 3,600,000 N/C, or 36,000 N/C.
