Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about a point O located at the center of mass?
Practice Questions
1 question
Q1
Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about a point O located at the center of mass?
(m1v1 + m2v2)
(m1v1 - m2v2)
m1v1 + m2v2
0
Total angular momentum is the sum of individual angular momenta, which is m1v1 + m2v2.
Questions & Step-by-step Solutions
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Q
Q: Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about a point O located at the center of mass?
Solution: Total angular momentum is the sum of individual angular momenta, which is m1v1 + m2v2.
Steps: 8
Step 1: Identify the two particles A and B with masses m1 and m2.
Step 2: Note the velocities of the particles: A has velocity v1 and B has velocity v2.
Step 3: Understand that the particles are moving in opposite directions.
Step 4: Recognize that angular momentum is calculated as the product of mass and velocity.
Step 5: Calculate the angular momentum of particle A as m1 * v1.
Step 6: Calculate the angular momentum of particle B as m2 * v2.
Step 7: Since the particles are moving in opposite directions, consider the direction of their angular momentum.
Step 8: Add the angular momenta of both particles to find the total angular momentum: Total Angular Momentum = m1 * v1 + m2 * v2.
