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Solve the equation sin(2x) = √3/2 for x in the interval [0, 2π].

Practice Questions

1 question
Q1
Solve the equation sin(2x) = √3/2 for x in the interval [0, 2π].
  1. π/12
  2. 5π/12
  3. 7π/12
  4. 11π/12

Questions & Step-by-step Solutions

1 item
Q
Q: Solve the equation sin(2x) = √3/2 for x in the interval [0, 2π].
Solution: The solutions are x = π/12, 5π/12, 7π/12, and 11π/12.
Steps: 0

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