In Young's double-slit experiment, if the distance between the slits is 0.2 mm and the distance from the slits to the screen is 1 m, what is the distance between the first and second bright fringes?
Practice Questions
1 question
Q1
In Young's double-slit experiment, if the distance between the slits is 0.2 mm and the distance from the slits to the screen is 1 m, what is the distance between the first and second bright fringes?
0.1 mm
0.2 mm
0.4 mm
0.6 mm
Distance between fringes (y) = (λD)/d. Assuming λ = 500 nm, y = (500 x 10^-9 * 1)/(0.2 x 10^-3) = 0.0025 m = 0.25 mm. Distance between first and second bright fringes = 0.4 mm.
Questions & Step-by-step Solutions
1 item
Q
Q: In Young's double-slit experiment, if the distance between the slits is 0.2 mm and the distance from the slits to the screen is 1 m, what is the distance between the first and second bright fringes?
Solution: Distance between fringes (y) = (λD)/d. Assuming λ = 500 nm, y = (500 x 10^-9 * 1)/(0.2 x 10^-3) = 0.0025 m = 0.25 mm. Distance between first and second bright fringes = 0.4 mm.
Steps: 7
Step 1: Identify the given values from the problem. The distance between the slits (d) is 0.2 mm, the distance from the slits to the screen (D) is 1 m, and we assume the wavelength (λ) is 500 nm.
Step 2: Convert all measurements to the same unit. Convert 0.2 mm to meters: 0.2 mm = 0.2 x 10^-3 m. Convert 500 nm to meters: 500 nm = 500 x 10^-9 m.
Step 3: Use the formula for the distance between fringes (y) which is y = (λD)/d.
Step 4: Substitute the values into the formula: y = (500 x 10^-9 m * 1 m) / (0.2 x 10^-3 m).
Step 5: Calculate the value: y = (500 x 10^-9) / (0.2 x 10^-3) = 0.0025 m.
Step 6: Convert the distance y from meters to millimeters: 0.0025 m = 0.25 mm.
Step 7: The distance between the first and second bright fringes is twice the distance between the fringes: 2y = 2 * 0.25 mm = 0.5 mm.
