In which of the following compounds does the central atom exhibit sp3d2 hybridization?
Practice Questions
1 question
Q1
In which of the following compounds does the central atom exhibit sp3d2 hybridization?
SF6
XeF4
NH3
CCl4
In SF6 (sulfur hexafluoride), the sulfur atom is sp3d2 hybridized, allowing it to form six sigma bonds with fluorine atoms.
Questions & Step-by-step Solutions
1 item
Q
Q: In which of the following compounds does the central atom exhibit sp3d2 hybridization?
Solution: In SF6 (sulfur hexafluoride), the sulfur atom is sp3d2 hybridized, allowing it to form six sigma bonds with fluorine atoms.
Steps: 7
Step 1: Understand what hybridization means. Hybridization is the mixing of atomic orbitals to form new hybrid orbitals for bonding.
Step 2: Identify the types of hybridization. sp3d2 hybridization involves one s orbital, three p orbitals, and two d orbitals.
Step 3: Determine the number of bonds and lone pairs around the central atom. For sp3d2, the central atom should have six bonding pairs and no lone pairs.
Step 4: Look at the compound SF6 (sulfur hexafluoride). The central atom is sulfur.
Step 5: Count the number of fluorine atoms bonded to sulfur in SF6. There are six fluorine atoms, which means six sigma bonds.
Step 6: Since sulfur in SF6 forms six bonds and has no lone pairs, it uses sp3d2 hybridization.
Step 7: Conclude that in SF6, the central atom (sulfur) exhibits sp3d2 hybridization.
