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In the reaction 2Ag^+ + Zn → 2Ag + Zn^2+, what is the oxidation state change for
In the reaction 2Ag^+ + Zn → 2Ag + Zn^2+, what is the oxidation state change for zinc?
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Practice Questions
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Q1
In the reaction 2Ag^+ + Zn → 2Ag + Zn^2+, what is the oxidation state change for zinc?
0 to +2
+2 to 0
+2 to +1
0 to -1
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Zinc is oxidized from an oxidation state of 0 to +2.
Questions & Step-by-step Solutions
1 item
Q
Q: In the reaction 2Ag^+ + Zn → 2Ag + Zn^2+, what is the oxidation state change for zinc?
Solution:
Zinc is oxidized from an oxidation state of 0 to +2.
Steps: 5
Show Steps
Step 1: Identify the reactants in the reaction, which are 2Ag^+ and Zn.
Step 2: Determine the oxidation state of zinc (Zn) in its elemental form. Elemental zinc has an oxidation state of 0.
Step 3: Look at the products of the reaction, which include Zn^2+. This indicates that zinc has lost electrons.
Step 4: Identify the oxidation state of zinc in the product Zn^2+. The oxidation state of Zn^2+ is +2.
Step 5: Calculate the change in oxidation state for zinc. It goes from 0 to +2, which is an increase of 2.
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