In an RLC series circuit, if the resistance is increased while keeping the inductance and capacitance constant, what happens to the quality factor (Q)?
Practice Questions
1 question
Q1
In an RLC series circuit, if the resistance is increased while keeping the inductance and capacitance constant, what happens to the quality factor (Q)?
Increases
Decreases
Remains the same
Becomes zero
The quality factor (Q) is given by Q = (1/R)√(L/C). Increasing R decreases Q.
Questions & Step-by-step Solutions
1 item
Q
Q: In an RLC series circuit, if the resistance is increased while keeping the inductance and capacitance constant, what happens to the quality factor (Q)?
Solution: The quality factor (Q) is given by Q = (1/R)√(L/C). Increasing R decreases Q.
Steps: 7
Step 1: Understand what an RLC series circuit is. It consists of a resistor (R), an inductor (L), and a capacitor (C) connected in series.
Step 2: Know what the quality factor (Q) is. It measures how underdamped an oscillator or resonator is, and it is calculated using the formula Q = (1/R)√(L/C).
Step 3: Identify the components of the formula. R is resistance, L is inductance, and C is capacitance.
Step 4: Recognize that in this scenario, the inductance (L) and capacitance (C) are kept constant.
Step 5: Focus on the effect of increasing resistance (R). When R increases, the value of (1/R) decreases.
Step 6: Since Q is directly proportional to (1/R), if (1/R) decreases, then Q also decreases.
Step 7: Conclude that increasing the resistance in the circuit while keeping inductance and capacitance constant results in a decrease in the quality factor (Q).
