In an electrophilic addition reaction of HBr to propene, what is the major product formed?

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Q: In an electrophilic addition reaction of HBr to propene, what is the major product formed?

Solution: The major product is 2-bromopropane due to Markovnikov's rule, where the bromine adds to the more substituted carbon.

Steps: 5

Step 1: Identify the reactants. We have propene (a three-carbon alkene) and HBr (hydrobromic acid).
Step 2: Understand the structure of propene. Propene has a double bond between the first and second carbon atoms.
Step 3: Recall Markovnikov's rule. This rule states that when HX (like HBr) adds to an alkene, the hydrogen (H) will attach to the carbon with more hydrogen atoms already (the less substituted carbon), and the halide (Br) will attach to the carbon with fewer hydrogen atoms (the more substituted carbon).
Step 4: Apply Markovnikov's rule to propene. The first carbon (C1) has 2 hydrogen atoms, and the second carbon (C2) has 1 hydrogen atom. Therefore, H will attach to C1, and Br will attach to C2.
Step 5: Write the product. The product formed is 2-bromopropane, where the bromine is on the second carbon.