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In a rotating system, if the angular momentum is doubled while the moment of ine
In a rotating system, if the angular momentum is doubled while the moment of inertia remains constant, what happens to the angular velocity?
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Practice Questions
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Q1
In a rotating system, if the angular momentum is doubled while the moment of inertia remains constant, what happens to the angular velocity?
It doubles
It halves
It remains the same
It quadruples
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Since L = Iω, if L is doubled and I remains constant, then ω must also double.
Questions & Step-by-step Solutions
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Q
Q: In a rotating system, if the angular momentum is doubled while the moment of inertia remains constant, what happens to the angular velocity?
Solution:
Since L = Iω, if L is doubled and I remains constant, then ω must also double.
Steps: 8
Show Steps
Step 1: Understand the formula for angular momentum, which is L = Iω, where L is angular momentum, I is moment of inertia, and ω is angular velocity.
Step 2: Identify that in this problem, the moment of inertia (I) remains constant.
Step 3: Recognize that if the angular momentum (L) is doubled, we can express this as 2L.
Step 4: Set up the equation with the new angular momentum: 2L = Iω'. Here, ω' is the new angular velocity we want to find.
Step 5: Since L = Iω, we can replace L in the equation: 2(Iω) = Iω'.
Step 6: Simplify the equation: 2Iω = Iω'.
Step 7: Since I is constant and not zero, we can divide both sides by I: 2ω = ω'.
Step 8: This shows that the new angular velocity (ω') is double the original angular velocity (ω).
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