In a group of 100 people, 60 like football, 30 like basketball, and 10 like both. What is the probability that a person likes football given that they like basketball?
Practice Questions
1 question
Q1
In a group of 100 people, 60 like football, 30 like basketball, and 10 like both. What is the probability that a person likes football given that they like basketball?
0.5
0.3
0.6
0.7
Using conditional probability, P(Football | Basketball) = P(Football and Basketball) / P(Basketball) = 10/30 = 1/3.
Questions & Step-by-step Solutions
1 item
Q
Q: In a group of 100 people, 60 like football, 30 like basketball, and 10 like both. What is the probability that a person likes football given that they like basketball?
Solution: Using conditional probability, P(Football | Basketball) = P(Football and Basketball) / P(Basketball) = 10/30 = 1/3.
Steps: 9
Step 1: Identify the total number of people in the group, which is 100.
Step 2: Identify how many people like basketball, which is 30.
Step 3: Identify how many people like both football and basketball, which is 10.
Step 4: Calculate the probability of a person liking both football and basketball, which is P(Football and Basketball) = 10/100.
Step 5: Calculate the probability of a person liking basketball, which is P(Basketball) = 30/100.
Step 6: Use the formula for conditional probability: P(Football | Basketball) = P(Football and Basketball) / P(Basketball).