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In a closed system, if the temperature of an ideal gas is doubled while keeping
In a closed system, if the temperature of an ideal gas is doubled while keeping the pressure constant, what happens to its volume?
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Practice Questions
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Q1
In a closed system, if the temperature of an ideal gas is doubled while keeping the pressure constant, what happens to its volume?
It halves
It doubles
It remains the same
It quadruples
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According to Charles's Law, V1/T1 = V2/T2. If T2 = 2T1, then V2 = 2V1.
Questions & Step-by-step Solutions
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Q
Q: In a closed system, if the temperature of an ideal gas is doubled while keeping the pressure constant, what happens to its volume?
Solution:
According to Charles's Law, V1/T1 = V2/T2. If T2 = 2T1, then V2 = 2V1.
Steps: 8
Show Steps
Step 1: Understand that we are dealing with an ideal gas in a closed system.
Step 2: Remember that we need to keep the pressure constant while changing the temperature.
Step 3: Recall Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is constant.
Step 4: Write down Charles's Law formula: V1/T1 = V2/T2.
Step 5: Identify the initial temperature (T1) and the new temperature (T2). If T2 is double T1, then T2 = 2T1.
Step 6: Substitute T2 into the formula: V1/T1 = V2/(2T1).
Step 7: Rearrange the equation to find V2: V2 = 2 * V1.
Step 8: Conclude that if the temperature is doubled, the volume also doubles.
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