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In a circuit with a 10V battery and two resistors of 5 ohms each in series, what
In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?
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Practice Questions
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Q1
In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?
1 A
2 A
0.5 A
5 A
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Total resistance R_total = 5 + 5 = 10 ohms. Current I = V/R_total = 10V / 10 ohms = 1 A.
Questions & Step-by-step Solutions
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Q
Q: In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?
Solution:
Total resistance R_total = 5 + 5 = 10 ohms. Current I = V/R_total = 10V / 10 ohms = 1 A.
Steps: 6
Show Steps
Step 1: Identify the voltage of the battery, which is 10V.
Step 2: Identify the resistors in the circuit. There are two resistors, each with a resistance of 5 ohms.
Step 3: Calculate the total resistance in the circuit. Since the resistors are in series, add their resistances: 5 ohms + 5 ohms = 10 ohms.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R).
Step 5: Substitute the values into the formula: I = 10V / 10 ohms.
Step 6: Calculate the current: 10V / 10 ohms = 1 A.
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