In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and pure B is 40 mmHg, what is the total vapor pressure when the mole fraction of A is 0.5?
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Q1
In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and pure B is 40 mmHg, what is the total vapor pressure when the mole fraction of A is 0.5?
Q: In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and pure B is 40 mmHg, what is the total vapor pressure when the mole fraction of A is 0.5?
Step 1: Identify the vapor pressure of pure A, which is 80 mmHg.
Step 2: Identify the vapor pressure of pure B, which is 40 mmHg.
Step 3: Determine the mole fraction of A, which is given as 0.5.
Step 4: Calculate the contribution to the vapor pressure from A using the formula: P_A = mole fraction of A * vapor pressure of pure A. So, P_A = 0.5 * 80 = 40 mmHg.
Step 5: Calculate the contribution to the vapor pressure from B using the formula: P_B = mole fraction of B * vapor pressure of pure B. Since the mole fraction of B is 1 - mole fraction of A, it is 1 - 0.5 = 0.5. So, P_B = 0.5 * 40 = 20 mmHg.
Step 6: Add the contributions from A and B to find the total vapor pressure: Total vapor pressure = P_A + P_B = 40 mmHg + 20 mmHg = 60 mmHg.
