If the resistivity of a material is 1.5 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 0.5 mm²?
Practice Questions
1 question
Q1
If the resistivity of a material is 1.5 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 0.5 mm²?
0.09 Ω
0.18 Ω
0.27 Ω
0.36 Ω
Resistance R = ρ(L/A) = (1.5 x 10^-8)(3)/(0.5 x 10^-6) = 0.09 Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: If the resistivity of a material is 1.5 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 0.5 mm²?
Solution: Resistance R = ρ(L/A) = (1.5 x 10^-8)(3)/(0.5 x 10^-6) = 0.09 Ω.
Steps: 8
Step 1: Identify the given values. The resistivity (ρ) is 1.5 x 10^-8 Ω·m, the length (L) of the wire is 3 m, and the cross-sectional area (A) is 0.5 mm².
Step 2: Convert the cross-sectional area from mm² to m². Since 1 mm² = 1 x 10^-6 m², we have 0.5 mm² = 0.5 x 10^-6 m².
Step 3: Use the formula for resistance: R = ρ(L/A).
Step 4: Substitute the values into the formula: R = (1.5 x 10^-8)(3) / (0.5 x 10^-6).
Step 5: Calculate the numerator: (1.5 x 10^-8) * 3 = 4.5 x 10^-8.
Step 6: Calculate the denominator: (0.5 x 10^-6) = 0.5 x 10^-6.
Step 7: Now divide the numerator by the denominator: R = (4.5 x 10^-8) / (0.5 x 10^-6).
Step 8: Perform the division: R = 4.5 / 0.5 x 10^-8 / 10^-6 = 9 x 10^(-8 + 6) = 9 x 10^-2 = 0.09 Ω.
