If the resistance values in a Wheatstone bridge are R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what is the value of R4 for the bridge to be balanced?

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Q: If the resistance values in a Wheatstone bridge are R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what is the value of R4 for the bridge to be balanced?

Solution: Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.

Steps: 7

Step 1: Write down the given resistance values: R1 = 10Ω, R2 = 20Ω, R3 = 15Ω.
Step 2: Understand the balance condition of a Wheatstone bridge, which is R1/R2 = R3/R4.
Step 3: Rearrange the balance condition to solve for R4: R4 = (R2 * R3) / R1.
Step 4: Substitute the values into the equation: R4 = (20 * 15) / 10.
Step 5: Calculate the multiplication: 20 * 15 = 300.
Step 6: Divide the result by R1: 300 / 10 = 30.
Step 7: Conclude that the value of R4 for the bridge to be balanced is 30Ω.