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If a torque of 5 Nm is applied to a rotating object with a moment of inertia of
If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?
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Practice Questions
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Q1
If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?
2.5 rad/s²
5 rad/s²
10 rad/s²
1 rad/s²
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Angular acceleration α = Torque / Moment of inertia = 5 Nm / 2 kg·m² = 2.5 rad/s².
Questions & Step-by-step Solutions
1 item
Q
Q: If a torque of 5 Nm is applied to a rotating object with a moment of inertia of 2 kg·m², what is the angular acceleration?
Solution:
Angular acceleration α = Torque / Moment of inertia = 5 Nm / 2 kg·m² = 2.5 rad/s².
Steps: 5
Show Steps
Step 1: Understand the formula for angular acceleration, which is α = Torque / Moment of inertia.
Step 2: Identify the values given in the question: Torque = 5 Nm and Moment of inertia = 2 kg·m².
Step 3: Substitute the values into the formula: α = 5 Nm / 2 kg·m².
Step 4: Perform the division: 5 divided by 2 equals 2.5.
Step 5: Write the final answer: The angular acceleration α is 2.5 rad/s².
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