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If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from t
If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?
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Practice Questions
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Q1
If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?
50 N
45 N
40 N
30 N
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Force = Torque / Distance = 15 Nm / 0.3 m = 50 N.
Questions & Step-by-step Solutions
1 item
Q
Q: If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?
Solution:
Force = Torque / Distance = 15 Nm / 0.3 m = 50 N.
Steps: 6
Show Steps
Step 1: Understand that torque is calculated using the formula: Torque = Force x Distance.
Step 2: Rearrange the formula to find Force: Force = Torque / Distance.
Step 3: Substitute the given values into the formula: Torque = 15 Nm and Distance = 0.3 m.
Step 4: Calculate the Force: Force = 15 Nm / 0.3 m.
Step 5: Perform the division: 15 divided by 0.3 equals 50.
Step 6: Conclude that the magnitude of the force is 50 N.
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