If a person lifts a 50 kg object to a height of 2 meters in 5 seconds, what is the power exerted?

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Q: If a person lifts a 50 kg object to a height of 2 meters in 5 seconds, what is the power exerted?

Solution: The work done is W = mgh = 50 kg * 9.8 m/s^2 * 2 m = 980 J. Power is W/t = 980 J / 5 s = 196 W, approximately 200 W.

Steps: 9

Step 1: Identify the mass of the object. In this case, the mass (m) is 50 kg.
Step 2: Identify the height the object is lifted. Here, the height (h) is 2 meters.
Step 3: Use the acceleration due to gravity (g), which is approximately 9.8 m/s².
Step 4: Calculate the work done (W) using the formula W = mgh. Substitute the values: W = 50 kg * 9.8 m/s² * 2 m.
Step 5: Perform the multiplication: 50 * 9.8 * 2 = 980 Joules (J).
Step 6: Identify the time taken to lift the object, which is 5 seconds.
Step 7: Calculate the power (P) using the formula P = W/t. Substitute the values: P = 980 J / 5 s.
Step 8: Perform the division: 980 / 5 = 196 Watts (W).
Step 9: Round the answer to the nearest hundred if needed. Here, 196 W is approximately 200 W.