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If a person lifts a 10 kg object to a height of 5 m in 2 seconds, what is the po
If a person lifts a 10 kg object to a height of 5 m in 2 seconds, what is the power exerted?
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Q1
If a person lifts a 10 kg object to a height of 5 m in 2 seconds, what is the power exerted?
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First, calculate the work done: W = mgh = 10 kg * 9.8 m/s² * 5 m = 490 J. Then, P = W/t = 490 J / 2 s = 245 W.
Questions & Step-by-step Solutions
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Q
Q: If a person lifts a 10 kg object to a height of 5 m in 2 seconds, what is the power exerted?
Solution:
First, calculate the work done: W = mgh = 10 kg * 9.8 m/s² * 5 m = 490 J. Then, P = W/t = 490 J / 2 s = 245 W.
Steps: 8
Show Steps
Step 1: Identify the mass of the object. In this case, it is 10 kg.
Step 2: Identify the height to which the object is lifted. Here, it is 5 m.
Step 3: Use the formula for gravitational force, which is approximately 9.8 m/s².
Step 4: Calculate the work done (W) using the formula W = mgh. Substitute the values: W = 10 kg * 9.8 m/s² * 5 m.
Step 5: Perform the multiplication: 10 * 9.8 * 5 = 490 J. So, the work done is 490 Joules.
Step 6: Identify the time taken to lift the object, which is 2 seconds.
Step 7: Use the formula for power (P), which is P = W/t. Substitute the values: P = 490 J / 2 s.
Step 8: Perform the division: 490 J / 2 = 245 W. So, the power exerted is 245 Watts.
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