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If a force of 15 N is applied at an angle of 60° to the horizontal while moving
If a force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m, what is the work done by the force?
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Practice Questions
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Q1
If a force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m, what is the work done by the force?
30 J
60 J
120 J
180 J
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Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.
Questions & Step-by-step Solutions
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Q
Q: If a force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m, what is the work done by the force?
Solution:
Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.
Steps: 8
Show Steps
Step 1: Identify the force applied, which is 15 N.
Step 2: Identify the distance moved by the object, which is 4 m.
Step 3: Identify the angle at which the force is applied, which is 60°.
Step 4: Use the formula for work done: Work = Force × Distance × cos(Angle).
Step 5: Substitute the values into the formula: Work = 15 N × 4 m × cos(60°).
Step 6: Calculate cos(60°), which is 0.5.
Step 7: Substitute cos(60°) into the formula: Work = 15 N × 4 m × 0.5.
Step 8: Calculate the work done: Work = 15 × 4 × 0.5 = 30 J.
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